Integrand size = 22, antiderivative size = 157 \[ \int \frac {(e x)^{-1+n}}{\left (a+b \sec \left (c+d x^n\right )\right )^2} \, dx=\frac {(e x)^n}{a^2 e n}-\frac {2 b \left (2 a^2-b^2\right ) x^{-n} (e x)^n \text {arctanh}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} \left (c+d x^n\right )\right )}{\sqrt {a+b}}\right )}{a^2 (a-b)^{3/2} (a+b)^{3/2} d e n}+\frac {b^2 x^{-n} (e x)^n \tan \left (c+d x^n\right )}{a \left (a^2-b^2\right ) d e n \left (a+b \sec \left (c+d x^n\right )\right )} \]
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Time = 0.42 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.318, Rules used = {4293, 4289, 3870, 4004, 3916, 2738, 214} \[ \int \frac {(e x)^{-1+n}}{\left (a+b \sec \left (c+d x^n\right )\right )^2} \, dx=-\frac {2 b \left (2 a^2-b^2\right ) x^{-n} (e x)^n \text {arctanh}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} \left (c+d x^n\right )\right )}{\sqrt {a+b}}\right )}{a^2 d e n (a-b)^{3/2} (a+b)^{3/2}}+\frac {b^2 x^{-n} (e x)^n \tan \left (c+d x^n\right )}{a d e n \left (a^2-b^2\right ) \left (a+b \sec \left (c+d x^n\right )\right )}+\frac {(e x)^n}{a^2 e n} \]
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Rule 214
Rule 2738
Rule 3870
Rule 3916
Rule 4004
Rule 4289
Rule 4293
Rubi steps \begin{align*} \text {integral}& = \frac {\left (x^{-n} (e x)^n\right ) \int \frac {x^{-1+n}}{\left (a+b \sec \left (c+d x^n\right )\right )^2} \, dx}{e} \\ & = \frac {\left (x^{-n} (e x)^n\right ) \text {Subst}\left (\int \frac {1}{(a+b \sec (c+d x))^2} \, dx,x,x^n\right )}{e n} \\ & = \frac {b^2 x^{-n} (e x)^n \tan \left (c+d x^n\right )}{a \left (a^2-b^2\right ) d e n \left (a+b \sec \left (c+d x^n\right )\right )}-\frac {\left (x^{-n} (e x)^n\right ) \text {Subst}\left (\int \frac {-a^2+b^2+a b \sec (c+d x)}{a+b \sec (c+d x)} \, dx,x,x^n\right )}{a \left (a^2-b^2\right ) e n} \\ & = \frac {(e x)^n}{a^2 e n}+\frac {b^2 x^{-n} (e x)^n \tan \left (c+d x^n\right )}{a \left (a^2-b^2\right ) d e n \left (a+b \sec \left (c+d x^n\right )\right )}+\frac {\left (\left (-a^2 b+b \left (-a^2+b^2\right )\right ) x^{-n} (e x)^n\right ) \text {Subst}\left (\int \frac {\sec (c+d x)}{a+b \sec (c+d x)} \, dx,x,x^n\right )}{a^2 \left (a^2-b^2\right ) e n} \\ & = \frac {(e x)^n}{a^2 e n}+\frac {b^2 x^{-n} (e x)^n \tan \left (c+d x^n\right )}{a \left (a^2-b^2\right ) d e n \left (a+b \sec \left (c+d x^n\right )\right )}+\frac {\left (\left (-a^2 b+b \left (-a^2+b^2\right )\right ) x^{-n} (e x)^n\right ) \text {Subst}\left (\int \frac {1}{1+\frac {a \cos (c+d x)}{b}} \, dx,x,x^n\right )}{a^2 b \left (a^2-b^2\right ) e n} \\ & = \frac {(e x)^n}{a^2 e n}+\frac {b^2 x^{-n} (e x)^n \tan \left (c+d x^n\right )}{a \left (a^2-b^2\right ) d e n \left (a+b \sec \left (c+d x^n\right )\right )}+\frac {\left (2 \left (-a^2 b+b \left (-a^2+b^2\right )\right ) x^{-n} (e x)^n\right ) \text {Subst}\left (\int \frac {1}{1+\frac {a}{b}+\left (1-\frac {a}{b}\right ) x^2} \, dx,x,\tan \left (\frac {1}{2} \left (c+d x^n\right )\right )\right )}{a^2 b \left (a^2-b^2\right ) d e n} \\ & = \frac {(e x)^n}{a^2 e n}-\frac {2 b \left (2 a^2-b^2\right ) x^{-n} (e x)^n \text {arctanh}\left (\frac {\sqrt {a-b} \tan \left (\frac {1}{2} \left (c+d x^n\right )\right )}{\sqrt {a+b}}\right )}{a^2 (a-b)^{3/2} (a+b)^{3/2} d e n}+\frac {b^2 x^{-n} (e x)^n \tan \left (c+d x^n\right )}{a \left (a^2-b^2\right ) d e n \left (a+b \sec \left (c+d x^n\right )\right )} \\ \end{align*}
Time = 1.69 (sec) , antiderivative size = 191, normalized size of antiderivative = 1.22 \[ \int \frac {(e x)^{-1+n}}{\left (a+b \sec \left (c+d x^n\right )\right )^2} \, dx=\frac {x^{-n} (e x)^n \left (-2 b \left (-2 a^2+b^2\right ) \text {arctanh}\left (\frac {(-a+b) \tan \left (\frac {1}{2} \left (c+d x^n\right )\right )}{\sqrt {a^2-b^2}}\right ) \left (b+a \cos \left (c+d x^n\right )\right )+\sqrt {a^2-b^2} \left (a \left (a^2-b^2\right ) \left (c+d x^n\right ) \cos \left (c+d x^n\right )+b \left (\left (a^2-b^2\right ) \left (c+d x^n\right )+a b \sin \left (c+d x^n\right )\right )\right )\right )}{a^2 (a-b) (a+b) \sqrt {a^2-b^2} d e n \left (b+a \cos \left (c+d x^n\right )\right )} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 1.72 (sec) , antiderivative size = 638, normalized size of antiderivative = 4.06
method | result | size |
risch | \(\frac {x \,{\mathrm e}^{\frac {\left (-1+n \right ) \left (-i \pi \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )+i \pi \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i e x \right )^{2}+i \pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )^{2}-i \pi \operatorname {csgn}\left (i e x \right )^{3}+2 \ln \left (x \right )+2 \ln \left (e \right )\right )}{2}}}{a^{2} n}+\frac {2 i b^{2} e^{n} \left (-1\right )^{\frac {\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )}{2}} \left (b \,{\mathrm e}^{\frac {i \left (-\pi n \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )+\pi n \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i e x \right )^{2}+\pi n \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )^{2}-\pi n \operatorname {csgn}\left (i e x \right )^{3}-\pi \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i e x \right )^{2}-\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )^{2}+\pi \operatorname {csgn}\left (i e x \right )^{3}+2 d \,x^{n}+2 c \right )}{2}}+{\mathrm e}^{\frac {i \pi \,\operatorname {csgn}\left (i e x \right ) \left (-\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i x \right ) n +\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i e x \right ) n +\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right ) n -\operatorname {csgn}\left (i e x \right )^{2} n -\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i e x \right )-\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )+\operatorname {csgn}\left (i e x \right )^{2}\right )}{2}} a \right )}{a^{2} \left (a^{2}-b^{2}\right ) d n \left (a \,{\mathrm e}^{2 i \left (c +d \,x^{n}\right )}+2 b \,{\mathrm e}^{i \left (c +d \,x^{n}\right )}+a \right ) e}+\frac {2 i \arctan \left (\frac {2 a \,{\mathrm e}^{i \left (d \,x^{n}+2 c \right )}+2 \,{\mathrm e}^{i c} b}{2 \sqrt {a^{2} {\mathrm e}^{2 i c}-{\mathrm e}^{2 i c} b^{2}}}\right ) e^{n} \left (-2 a^{2}+b^{2}\right ) b \,{\mathrm e}^{\frac {i \left (-\pi n \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )+\pi n \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i e x \right )^{2}+\pi n \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )^{2}-\pi n \operatorname {csgn}\left (i e x \right )^{3}+\pi \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )-\pi \,\operatorname {csgn}\left (i e \right ) \operatorname {csgn}\left (i e x \right )^{2}-\pi \,\operatorname {csgn}\left (i x \right ) \operatorname {csgn}\left (i e x \right )^{2}+\pi \operatorname {csgn}\left (i e x \right )^{3}+2 c \right )}{2}}}{\sqrt {a^{2} {\mathrm e}^{2 i c}-{\mathrm e}^{2 i c} b^{2}}\, d e n \left (-a^{2}+b^{2}\right ) a^{2}}\) | \(638\) |
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Time = 0.32 (sec) , antiderivative size = 628, normalized size of antiderivative = 4.00 \[ \int \frac {(e x)^{-1+n}}{\left (a+b \sec \left (c+d x^n\right )\right )^2} \, dx=\left [\frac {2 \, {\left (a^{5} - 2 \, a^{3} b^{2} + a b^{4}\right )} d e^{n - 1} x^{n} \cos \left (d x^{n} + c\right ) + 2 \, {\left (a^{4} b - 2 \, a^{2} b^{3} + b^{5}\right )} d e^{n - 1} x^{n} + 2 \, {\left (a^{3} b^{2} - a b^{4}\right )} e^{n - 1} \sin \left (d x^{n} + c\right ) + {\left ({\left (2 \, a^{3} b - a b^{3}\right )} \sqrt {a^{2} - b^{2}} e^{n - 1} \cos \left (d x^{n} + c\right ) + {\left (2 \, a^{2} b^{2} - b^{4}\right )} \sqrt {a^{2} - b^{2}} e^{n - 1}\right )} \log \left (\frac {2 \, a b \cos \left (d x^{n} + c\right ) - {\left (a^{2} - 2 \, b^{2}\right )} \cos \left (d x^{n} + c\right )^{2} + 2 \, a^{2} - b^{2} - 2 \, {\left (\sqrt {a^{2} - b^{2}} b \cos \left (d x^{n} + c\right ) + \sqrt {a^{2} - b^{2}} a\right )} \sin \left (d x^{n} + c\right )}{a^{2} \cos \left (d x^{n} + c\right )^{2} + 2 \, a b \cos \left (d x^{n} + c\right ) + b^{2}}\right )}{2 \, {\left ({\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )} d n \cos \left (d x^{n} + c\right ) + {\left (a^{6} b - 2 \, a^{4} b^{3} + a^{2} b^{5}\right )} d n\right )}}, \frac {{\left (a^{5} - 2 \, a^{3} b^{2} + a b^{4}\right )} d e^{n - 1} x^{n} \cos \left (d x^{n} + c\right ) + {\left (a^{4} b - 2 \, a^{2} b^{3} + b^{5}\right )} d e^{n - 1} x^{n} + {\left (a^{3} b^{2} - a b^{4}\right )} e^{n - 1} \sin \left (d x^{n} + c\right ) - {\left ({\left (2 \, a^{3} b - a b^{3}\right )} \sqrt {-a^{2} + b^{2}} e^{n - 1} \cos \left (d x^{n} + c\right ) + {\left (2 \, a^{2} b^{2} - b^{4}\right )} \sqrt {-a^{2} + b^{2}} e^{n - 1}\right )} \arctan \left (-\frac {\sqrt {-a^{2} + b^{2}} b \cos \left (d x^{n} + c\right ) + \sqrt {-a^{2} + b^{2}} a}{{\left (a^{2} - b^{2}\right )} \sin \left (d x^{n} + c\right )}\right )}{{\left (a^{7} - 2 \, a^{5} b^{2} + a^{3} b^{4}\right )} d n \cos \left (d x^{n} + c\right ) + {\left (a^{6} b - 2 \, a^{4} b^{3} + a^{2} b^{5}\right )} d n}\right ] \]
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\[ \int \frac {(e x)^{-1+n}}{\left (a+b \sec \left (c+d x^n\right )\right )^2} \, dx=\int \frac {\left (e x\right )^{n - 1}}{\left (a + b \sec {\left (c + d x^{n} \right )}\right )^{2}}\, dx \]
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\[ \int \frac {(e x)^{-1+n}}{\left (a+b \sec \left (c+d x^n\right )\right )^2} \, dx=\int { \frac {\left (e x\right )^{n - 1}}{{\left (b \sec \left (d x^{n} + c\right ) + a\right )}^{2}} \,d x } \]
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\[ \int \frac {(e x)^{-1+n}}{\left (a+b \sec \left (c+d x^n\right )\right )^2} \, dx=\int { \frac {\left (e x\right )^{n - 1}}{{\left (b \sec \left (d x^{n} + c\right ) + a\right )}^{2}} \,d x } \]
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Time = 18.23 (sec) , antiderivative size = 461, normalized size of antiderivative = 2.94 \[ \int \frac {(e x)^{-1+n}}{\left (a+b \sec \left (c+d x^n\right )\right )^2} \, dx=\frac {\frac {b^2\,x\,{\left (e\,x\right )}^{n-1}\,2{}\mathrm {i}}{a\,d\,n\,x^n\,\left (a^2-b^2\right )}+\frac {b^3\,x\,{\mathrm {e}}^{c\,1{}\mathrm {i}+d\,x^n\,1{}\mathrm {i}}\,{\left (e\,x\right )}^{n-1}\,2{}\mathrm {i}}{a^2\,d\,n\,x^n\,\left (a^2-b^2\right )}}{a+a\,{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x^n\,2{}\mathrm {i}}+2\,b\,{\mathrm {e}}^{c\,1{}\mathrm {i}+d\,x^n\,1{}\mathrm {i}}}+\frac {x\,{\left (e\,x\right )}^{n-1}}{a^2\,n}+\frac {b\,x\,\ln \left (-2\,{\mathrm {e}}^{c\,1{}\mathrm {i}}\,{\mathrm {e}}^{d\,x^n\,1{}\mathrm {i}}\,\left (b^3\,x\,{\left (e\,x\right )}^{n-1}-2\,a^2\,b\,x\,{\left (e\,x\right )}^{n-1}\right )-\frac {b\,x\,\left (a^4-a^2\,b^2\right )\,\left (a+b\,{\mathrm {e}}^{c\,1{}\mathrm {i}}\,{\mathrm {e}}^{d\,x^n\,1{}\mathrm {i}}\right )\,{\left (e\,x\right )}^{n-1}\,\left (2\,a^2-b^2\right )\,2{}\mathrm {i}}{a^2\,{\left (a+b\right )}^{3/2}\,{\left (a-b\right )}^{3/2}}\right )\,{\left (e\,x\right )}^{n-1}\,\left (2\,a^2-b^2\right )}{a^2\,d\,n\,x^n\,{\left (a+b\right )}^{3/2}\,{\left (a-b\right )}^{3/2}}-\frac {b\,x\,\ln \left (-2\,{\mathrm {e}}^{c\,1{}\mathrm {i}}\,{\mathrm {e}}^{d\,x^n\,1{}\mathrm {i}}\,\left (b^3\,x\,{\left (e\,x\right )}^{n-1}-2\,a^2\,b\,x\,{\left (e\,x\right )}^{n-1}\right )+\frac {b\,x\,\left (a^4-a^2\,b^2\right )\,\left (a+b\,{\mathrm {e}}^{c\,1{}\mathrm {i}}\,{\mathrm {e}}^{d\,x^n\,1{}\mathrm {i}}\right )\,{\left (e\,x\right )}^{n-1}\,\left (2\,a^2-b^2\right )\,2{}\mathrm {i}}{a^2\,{\left (a+b\right )}^{3/2}\,{\left (a-b\right )}^{3/2}}\right )\,{\left (e\,x\right )}^{n-1}\,\left (2\,a^2-b^2\right )}{a^2\,d\,n\,x^n\,{\left (a+b\right )}^{3/2}\,{\left (a-b\right )}^{3/2}} \]
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